Explanation: The molecular composition of a water molecule is H2O. Hydrogen has a massive of 1, then multiplied by 2 because it has actually 2 atoms. Oxygen has actually a mass of 16 g. Therefore we add the both masses and the an outcome is 18 g/ mole

c12 has a fixed of 12 amu

Explanation:

mass of one mole that c12 = g. So mass that 1 atom that c12 = 1.9927e-23g

D) g

Explanation: The question asks to convert formula unit come grams. That is a unit counter problem.

1 mole equals to Avogadro number of formula units. So, to convert the given number of formula devices to moles, we have to divide by the Avogadro number. After ~ this, we do moles to grams conversion and also for this the moles room multiplied by the molar massive of the compound. Molar fixed of AgCl is 143.32 gram per mol.

You are watching: Calculate the mass, in grams, of a single silver atom (mag = 107.87 amu ).

= g

So, the correct option is D) g

1 atom mass unit is the fixed of an atom or the caliberates massive on atomic scale. The is likewise expressed in dalton denoted through Da whereas atom mass unit is denoted by amu.

1 amu deserve to be to express in grams together follows:

For convert in grams,

Thus, fixed of dare is 204.16 * 10^-2^4 g

2.38×10⁻²² g

Explanation:

Molar mass is characterized as the massive of 1 mole that the substance.

Since the molar massive fo AgCl is 143.32 g/mol

Since, 1 mole that AgCl has 6.022×10²³ molecule of AgCl

So,

6.022×10²³ molecules of AgCl has a mass of 143.32 g

Also,

1 molecule of AgCl has actually a massive of 143.32/6.022×10²³ g

Mass that 1 formula unit of AgCl is 2.38×10⁻²² g

7.307 x 10^-23

Explanation:

mass that one molecule = mr/ avogadros number

= 44/6.022 x 10^23

= 7.307x 10^-23

A. 3.53 g the Sulphur.

B. 1.79 x 10^-22 g of silver atom.

Explanation:

A.

Equation the the reaction

C + S + 2O2 --> CO2 + SO2

Molar mass of:

C = 12 g/mol

S = 32 g/mol

CO2 = 12 + (16*2)

= 44 g/mol

SO2 = 32 + (32*2)

= 64 g/mol

Mass of C + S = 9 g

Mass that CO2 + SO2 = 27.1 g

Therefore, mass of C = 9 - fixed of S;

Mass of C * ratio of molar massive of CO2 to C + massive of S * proportion of molar massive of SO2 to S,

(Moles of C*molar mass of CO2) + (Moles of S*molar massive of SO2) = 27.1

(9 - S) * (44/12) + S* (64/32)

(9 - S) * (3.67) + S * 2

33 - 3.67S + 2S = 27.1

-1.67S = - 5.9

Mass the S = 3.53 g

Mass that C = 9.0 - 3.53

= 12.53 g

The fixed of sulfur is 3.53 g.

B.

Calculate the mass, in grams, of a solitary silver atom (mAg = 107.87 amu ).

Number of moles of 1 silver- atom making use of Avogadros constant, 6.022 x 10^23 molecules per moles

Moles = 1/ 6.023 x 10^23

= 1.66*10^-24 moles

Mass = variety of moles * molar mass

Mass = 1.66 x 10 ^-24 * 107.87

Mass = 1.79 x 10^-22 g of silver atom.

Answer : The mass in grams that a single formula unit of silver- chloride will certainly be

Explanation:

Formula devices : that is defined as lowest entirety number proportion of ions in an ionic compound. The is calculation by multiplying the variety of moles by Avogadro"s number which is .

Single formula unit of silver chloride method that 1 mole of silver- chloride.

We are given :

Number of moles of silver- chloride = 1 moles

The molar fixed of silver chloride = 143.32 g/mole

That means, 1 mole silver chloride contains 143.32 grams of silver- chloride.

Now we have to determine the fixed in grams of a single formula unit of silver- chloride.

As, formula unit has actually mass = 143.32 g

So, 1 formula unit has mass =

Therefore, the mass in grams the a solitary formula unit of silver- chloride will be

Explanation: To calculate the massive of 1 Xe-atom , we will need atomic fixed of Xe which is 131.29amu.

This atomic mass is the massive of 1 mole of 1 Xe-atom. One mole the Xe-atom is

atom of Xe. We will use this relation to transform Mass the Xe-atom right into grams.

=

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