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You are watching: Enter a balanced equation for the combustion of ethanol.

This is an example of a combustion reaction. Come answer this girlfriend must very first balance the equation.
The easiest way is to collection up the reaction equation without any coefficients:
C2H6O + O2 --> CO2 + HOH
Now begin balancing, very first with carbon, then through hydrogen and last the oxygen.
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This is an instance of a burning reaction. Come answer this friend must very first balance the equation.
The easiest way is to set up the reaction equation without any coefficients:
C2H6O + O2 --> CO2 + HOH
Now begin balancing, very first with carbon, then v hydrogen and also last the oxygen.
There space 2 carbons on the left and 6 hydrogens for this reason you include a coefficient the 2 in prior of the CO2 and a 3 in prior of the water.
C2H6O + O2 --> 2 CO2 + 3 HOH
Now count the number of oxygen on the product side and also you acquire seven. One oxygen come from the ethanol so you require 6 an ext from oxygen. Add a coefficient the 3 in front of the oxygen top top the reactant side and your reaction is balanced.
C2H60 + 3 O2 --> 2 CO2 + 3 HOH
This reflects you that for every mole of ethanol, girlfriend will obtain 3 moles of water. For this reason if you start with 0.51 moles of ethanol, you will produce 3 x .51 or 1.53 mole of water.
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