Presentation on theme: "How numerous Skittles are In a 2.17 oz Bag? By: Ryan Riling & Tom Dougherty."— Presentation transcript:




You are watching: How many skittles are in a 2.17 oz bag

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2 How many Skittles are In a 2.17 ounce Bag? By: Ryan Riling & Tom Dougherty

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3 HistoryHistory -Skittles production originated in England -First introduced to United states in 1974 -Owned by Mars Inc. -Skittles factory are located in U.S, Victoria, Australia, and new Zealand -Advertising campaigns are linked with rainbows -“Taste the Rainbow”

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4 PurposePurpose -We want to determine whether or no Mars Inc. (producer that Skittles) was fairly filling their bags v the asserted amount. -We made decision to purchase 35 conventional sized bags of skittles (2.17 ounce) and test to recognize if Skittles consumer are getting their money’s worth.

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5 retail Stores -Acme  five 2.17 oz. Bags -Genuardi’s  five 2.17 oz. Bags -Giant  five 2.17 oz. Bags -Redner’s  five 2.17 oz. Bags -CVS  5 2.17 oz. Bags -Wawa  five 2.17 oz. Bags -7-11  five 2.17 oz. Bags complete = 35 BAGS

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6 DataData

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7 GraphsGraphs

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8 Graphs (Cont.) 5254565860626466687072 five Number an introduction Minimum = 53 Quartile 3 = 63 Quartile 1 = 56 preferably = 68 average = 59 variety of Skittles

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9 Stem Plot 5 53 54 5 5 5 56 6 6 6 7 7 7 7 58 8 8 9 9 9 9 9 9 60 62 2 2 3 3 3 64 4 5 66 6 68 shape = about Symmetric center = 59 spread = Minimum – 53 maximum – 68

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10 1 Var Stats x = 59.4286 Σx = 2080 Σx² = 124110 Sx = 3.8293 n = 35 Minimum = 53 Quartile 1 = 56 average = 59 Quartile 3 = 63 maximum = 68

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11 assumptions 1). SRS 1). 2). Normal populace 2). 35 ≥ 30 OR n ≥ 30

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12 HypothesisHypothesis -Ho:  = 60 skittles per 2.17 oz. Bag -Ha:  ≠ 60 skittles per 2.17 oz. Bag

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) =.3835 degrees Freedom: Df = n-1 =" > 13 TestsTests One Sample T-Test check Statistic: t* = x - µ s/ √n = P-Value: 2 * P(µ > -.8828) =.3835 levels Freedom: Df = n-1 = 34 -.8828

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) =.3835 degrees Freedom: Df = n-1 =" title="TestsTests One Sample T-Test test Statistic: t* = x - µ s/ √n = P-Value: 2 * P(µ > ) =.3835 degrees Freedom: Df = n-1 =">

14 exam (Cont.) Conclusion: us fail to refuse the null hypothesis since our p-value is higher than  =.05. We have enough evidence the the mean number of Skittles per 2.17 oz. Bag is 60 Skittles.

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15 trust Level (95%) confidence Level = x ± t*(s/ √ n) = (58.113, 60.744) We are 95% Confident the the mean number of Skittles every 2.17 oz. Bag is in between 58.113 and 60.744 Skittles.

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16 personal Opinions -We felt together though the was very tedious to counting the quantity of cones in every of the 35 bags -It was time-consuming to travel to every of the 7 shop to achieve the required amount of samples -We agree v our T-Test results and feel as though where ever before you pick to buy your Skittles from, girlfriend are getting a same amount per bag because that the price.

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17 ApplicationApplication -Although large had the best average variety of Skittles every bag, us feel together though it is unnecessary to go out of your means just come buy skittles at Giant. -We feel as though Mars Inc. Relatively manufactures and also packages their Skittles bags.

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- 7-11 cones bags space packaged most fairly and have actually an typical of 60.2 cones per bag.

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18 Bias/ErrorBias/Error -Incorrect Skittles counting -Mistake beginning data into lists -Obtaining skittles at assorted stores  decided the an initial available bags -Counting damaged or deformed cones

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