Answer: x = 2 or x = - 3. Rearrange all nonzero state to the left side of the equation: 4 x2 + 3 x - 24 + x = 0Combine like te

You are watching: What are the solutions of the equation 4x2 + 3x = 24 – x?

Answer: x = 2 or x = - 3. Rearrange all nonzero terms to the left next of the equation: 4 x2 + 3 x - 24 + x = 0Combine like te
Rearrange every nonzero terms to the left next of the equation: 4 x^2 + 3 x - 24 + x = 0Combine like terms: 4 x^2 + 4 x - 24 = 0Find 2 integers: eginequationegincases- 8 + 12 = 4\- 8 imes 12 = 4 imes (- 24)endcasesendequationRewrite the center term: 4 x^2 - 8 x + 12 x - 24 = 0Factor the an initial two terms and the last 2 terms respectively: 4 x (x - 2) + 12 (x - 2) = 0Extract the typical factor: 4 (x - 2) (x + 3) = 0Apply zero product property that at the very least one aspect is zero: x - 2 = 0 or x + 3 = 0Rearrange unknown terms to the left next of the equation: x = 2Rearrange unknown state to the left side of the equation: x = - 3Find the union that the solutions: x = 2 or x = - 3Answer: x = 2 or x = - 3  