nitrogen gas is define as N2. The moleculer mass will come to be 28. For its one mole it is of 28gram. According to mole ide in one mole over there is 6.022*10^23 moles are present. So mass the 1 molecule that nitogen gas is 28/(6.022*10^23) gram. Fix it and also u will gain answer.

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Actually mass of 1 atom the nitrogen is 14 u(u=atomic fixed unit) massive of 1 mole=mass that 1 atom of nitrogen * Avagadro"s no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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1 mole the Nitrogen has 28 g mass. As Nitrogen gas is comprised of 2 Nitrogen facets Each nitrogen has Atmoic fixed 14 g so N2 will have 2x14 = 28 g.
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As we recognize that no. Of moles = given mass/molar mass also no. Moles = no.of particles(atoms,molecules etc)/avogadro no.(No) as we understand Avogadro"s number=6.023*10^23 for this reason no. Of moles=1/6.023*10^23 molar mass of nitrogen = 14*2=28 for this reason no. Of mole = mass/28 1/6.023*10^23=mass/28 mass=28/6.023*10^23...
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Nitrogen constantly exists as a dimer therefore the fixed of the molecule is to be calculated by multiplying atom mass that nitrogen by 2 which method 14*2=28
Nitrogen molecular mass is 28 1mole the n2 is 28gram for 1molecule the nitrogen division 28by avagadro number 6.022 10^23 therefore ans will be 28/6.022 10^23=4.64 10^-23
14 grams massive = number of moles x molar fixed 1 mole= family member mass in grams that that particular element
mass of 1 mole=mass of 1 atom of nitrogen * Avagadro"s no. * 1.6 *10^ (-24)(since 1 amu=1.6* 10^(-24) gm) =14*6.022*10^(23)*1.6* 10^(-24) =14 gm
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