2.1: The Atomic concept of Matter2.2: The discovery of atomic Structure2.3: The modern View of atomic Structure2.4: atom Mass2.5: The routine Table2.6: Molecules and Molecular Compounds2.8: Naming inorganic Compounds2.9: Some straightforward Organic compounds

Why is it proper to represent the elemental type of helium together He however improper to represent the elemental form of hydrogen together H?

Why is it appropriate to stand for the elemental kind of chlorine together Cl2 however improper to represent the elemental form of calcium together Ca2?

Hydrogen exists together a diatomic molecule in its elemental form; helium does no exist as a diatomic molecule.

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Why is it ideal to represent the elemental form of helium together He but improper to stand for the elemental type of hydrogen as H?

Why is it appropriate to stand for the elemental form of chlorine as Cl2 however improper to represent the elemental type of calcium together Ca2?

Conceptual Answers

The contemporary atomic theory says that all issue is written of atoms. Atoms are the smallest components of an facet that maintain the identification of the element.

Numerical Problems

(Basic concept check) when 32.0 grams (g) of methane are melted in 128.0 g that oxygen, 88.0 g of carbon dioxide and also 72.0 g the water room produced. Which law is this an example of? (a) legislation of definite proportions (b) regulation of conservation of mass or (c) legislation of lot of proportions. (Law of conservation of Mass) 8.00 grams (g) the methane are melted in 32.00 g of oxygen. The reaction produces 22.00 g the carbon dioxide and also an unmeasured massive of water. What massive of water is produced? (Law of definite Proportions) two experiments using sodium and chlorine space performed. In the an initial experiment, 4.36 grams (g) sodium room reacted v 32.24 g that chlorine, utilizing up all the sodium. 11.08 g of sodium chloride was produced in the first experiment. In the second experiment, 4.20 g that chlorine reacted with 20.00 g that sodium, using up all the chlorine. 6.92 g the of salt chloride was created in the 2nd experiment. Display that these outcomes are continual with the regulation of consistent composition. (Law of conservation of Mass): 36.0 grams (g) of lumber are shed in oxygen. The commodities of this reaction sweet 74.4 g. (a) What fixed of oxygen is necessary in this reaction? (b) What mass of oxygen is needed to burn 8.00 lb of wood? 1 lb = 453.59237 g. (Law of identify Proportions): A sample the methane has only carbon and hydrogen, through 3.00 grams (g) that carbon because that every 1.00 g the hydrogen. Exactly how much hydrogen should be existing in a different, 50.0 g exact same of methane?

Numerical Solutions

The prize is (b) law of conservation of mass. The number of grams of reactants (32.0 g that methane and 128.0 g the oxygen = 160.0 g total) is same to the variety of grams the product (88.0 g that carbon dioxide and 72.0 g the water = 160.0 g total). The answer is 18.00 g that water. Since the only products are water and also carbon dioxide, their full mass need to equal the total mass the the reactants, methane and also oxygen. 8.00 g the methane + 32.00 g the oxygen = 40.00 total g of reactants. Due to the fact that the complete mass of the reactants equals the full mass the the products, the complete mass of the products is additionally 40.00 g. Thus, 40.00 full g of products = 22.00 g carbon dioxide + unknown mass water. 40.00 full g of assets - 22.00 g carbon dioxide = 18.00 g water.

To solve, identify the percent of salt in every sample of sodium chloride. Over there is 4.36 g sodium for every 11.08 g of salt chloride in the an initial experiment. The quantity of sodium in the salt chloride for the second experiment need to be found. This is uncovered by subtracted the known amount of reaction chlorine (4.20 g) indigenous the amount of sodium chloride (6.92 g). 6.92 g salt chloride - 4.20 g chlorine = 2.72 g sodium.

Thus, the percent of salt in each sample is stood for below: % Na = (4.36 g Na)/(11.08 g NaCl) x 100% = 39.4% Na % Na = (2.72 g Na)/(6.92 g NaCl) x 100% = 39.3% The slight distinction in compositions is early to significant figures: every percent has an suspicion of .01% in either direction. The 2 samples of sodium chloride have actually the exact same composition.

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The price is 38.4 g of oxygen. The complete mass the the assets is 74.4 g. Thus, the total mass that the reactants must equal 74.4 g together well. Thus, 74.4 g assets - 36.0 g lumber reactant = 38.4 g oxygen reactant. The answer is 8.53 lb of oxygen. From, (a) that it takes 38.4 g of oxygen come burn 18.0 g of wood. First, transform both the these values to pounds (alternatively, the 8.00 lb have the right to be convert to grams).

Now 2 ratios equal to every other can be set up to recognize the unknown fixed of oxygen.

The prize is 12.5 g the hydrogen. If there space 3.00 g of carbon existing for every 1.00 g of hydrogen, we can assume the smallest entirety number mix of these aspects in that proportion to it is in 4.00 g that methane: 50.0 g methane x (1.00 g hydrogen)/(4.00 g methane) = 12.5 g that hydrogen.

describe the experiment that provided evidence the the proton is positively charged. What monitoring led Rutherford to suggest the visibility of the neutron? What is the difference between Rutherford’s version of the atom and also the version altoalsimce.orgists use today? If cathode rays room not deflected once they pass v a region of space, what does this imply around the visibility or lack of a magnetic field perpendicular come the path of the rays in the region? describe the result that would be meant from Rutherford’s experiment if the charge on α particles had remained the same yet the nucleus were negatively charged. If the nucleus were neutral, what would have been the outcome? explain the differences between an α particle, a β particle, and a γ ray. Which has the greatest capacity to permeate matter?

Numerical Problems

Please be certain you are familiar with the topics debated in section 1.6 before proceeding to the number Problems.

utilizing the data in Table 1.3 and also the periodic table, calculation the portion of the massive of a silicon atom the is due to electrons. Protons. making use of the data in Table 1.3 and also the regular table, calculation the portion of the mass of a helium atom the is as result of electrons. Protons.
The radius of one atom is around 104 times bigger than the radius the its nucleus. If the radius the the nucleus were 1.0 cm, what would be the radius that the atom in centimeters? in miles? The full charge on an oil fall was uncovered to it is in 3.84 × 10−18 coulombs. What is the total variety of electrons had in the drop?